=-625+547+352-147+735-2200-65

=-1403

   (-652) - {(-547) - 352 - [ (-147) - (-735) + (2200 + 65)]}

=  (-652)  + 547 + 352 - 147 - 735 - 2200 - 65

=  - (652 - 352) + (547 - 147) - (735 + 65) - 2200

=  - 300 + 400 - 1000 - 2200

=   100 - (1000 + 2200)

= 100 - 3200

= 3100

(-652) - {(-547) - 352 - [(-147) - (-735) + (2200 + 65)]}

= (-652) - {(-547) - 352 - [(-147) + 735 + 2265]}

= (-652) - {(-547) - 352 - [588 + 2265]}

= (-652) - {(-547) - 352 - 2853}

= (-652) - {(-899) - 2853}

= (-652) - (-3752)

= (-652) + 3752

= 3100

\(B.6^2:2-3^2.2=36:2-9.2=18-18=0\)

\(D.2^4-50:25+13.7=16-2+91=105\)

\(E.2.\left[\left(195+35:7\right):8+195\right]-400=2.\left[\left(195+5\right):8+195\right]-400\)

\(=2.\left[200:8+195\right]-400=2.\left[25+195\right]-400=2.220-400=440-400=40\)

Bài 1:

$0,2-\frac{4}{7}+\frac{-6}{5}=\frac{1}{5}+\frac{-6}{5}-\frac{4}{7}$

$=\frac{-5}{5}-\frac{4}{7}=-1-\frac{4}{7}=\frac{-11}{7}$

b.

$=(\frac{-2}{3})^2+\frac{5}{6}+(-1)=\frac{4}{9}+\frac{5}{6}-1$

$=\frac{8}{18}+\frac{15}{18}-1=\frac{23}{18}-1=\frac{5}{18}$

c.

$=1+3+5+7+9=25$

Bài 2:

a. $-(0,5+x)-\frac{1}{3}=\frac{1}{6}$

$-(0,5+x)=\frac{1}{3}+\frac{1}{6}=\frac{1}{2}$

$0,5+x=\frac{-1}{2}$

$x=\frac{-1}{2}-0,5=-1$
b.

$(x+\frac{4}{9})(x-\frac{11}{5})=0$

$\Rightarrow x+\frac{4}{9}=0$ hoặc $x-\frac{11}{5}=0$

$\Rightarrow x=\frac{-4}{9}$ hoặc $x=\frac{11}{5}$

c.

$\frac{1}{3}-|\frac{5}{4}-2x|=\frac{1}{4}$

$|\frac{5}{4}-2x|=\frac{1}{3}-\frac{1}{4}=\frac{1}{12}$
$\Rightarrow \frac{5}{4}-2x=\frac{1}{12}$ hoặc $\frac{5}{4}-2x=\frac{-1}{12}$

$\Rightarrow x=\frac{1}{2}(\frac{5}{4}-\frac{1}{12})$ hoặc $x=\frac{1}{2}(\frac{5}{4}+\frac{1}{12})$

$\Rightarrow x=\frac{7}{12}$ hoặc $x=\frac{2}{3}$

72x(28-49)+28x(-49-72)

=72x(-21)+28x(-121)

=-1512+(-3388)

=-49900

Có 2 cách hiểu 

+ ) 72x( 28 - 49 ) + 28x( -49 - 72)

= 72x . 28 - 72x . 49 - 28x . 49 - 28x . 72 

= -72x . 49 - 28x . 49

= 49 . ( - 100x )

+) 72 . ( 28 - 49 ) + 28 . ( -49 - 72 )

= 72 . 28 - 72 . 49 -28 . 49 - 28 . 72

= -72 . 49 -28 . 49

= 49 . ( -100 ) = -4900

Gọi tổng của phép tính trên là A

\(A=15+2^4+2^5+2^6+...+2^{2022}\)

\(\Rightarrow2A=2+2^2+...+2^{2023}\)

\(\Rightarrow A=2^{2023}-1\)

`2-3 3/4:(5/8-20%)`
`=2-3 3/4:(5/8-1/4)`
`=2-15/4:3/8`
`=2-10`
`=-8`

\(2-3\dfrac{3}{4}:\left(\dfrac{5}{8}-20\%\right)\)
\(=2-\dfrac{15}{4}:\left(\dfrac{5}{8}-\dfrac{20}{100}\right)\)

\(=\dfrac{2}{1}-\dfrac{15}{4}:\left(\dfrac{5}{8}-\dfrac{1}{5}\right)\)

\(=\dfrac{2}{1}-\dfrac{15}{4}:\left(\dfrac{25}{40}-\dfrac{8}{40}\right)\)

\(=\dfrac{2}{1}-\dfrac{15}{4}:\dfrac{17}{40}\)

\(=\dfrac{2}{1}-\dfrac{15}{4}.\dfrac{40}{17}\)

\(=\dfrac{2}{1}-\dfrac{600}{68}\)

\(=\dfrac{2}{1}-\dfrac{150}{17}\)

\(=\dfrac{34}{17}-\dfrac{150}{17}\)

\(=\dfrac{-116}{17}\)

\(2-3\dfrac{3}{4}:\left(\dfrac{5}{8}-20\%\right)\) 

\(=2-\dfrac{15}{4}:\left(\dfrac{5}{8}-\dfrac{1}{5}\right)\) 

\(=2-\dfrac{15}{4}:\dfrac{17}{40}\) 

\(=2-\dfrac{150}{17}\) 

\(=\dfrac{-116}{17}\)